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Test Test Test

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So...

E^2 - (pc)^2 = (m_0 c^2)^2

I'm pretty sure

K.E. = \frac{m_0 c^2}{\sqrt{1 - \frac{v^2}{c^2}} } - m_0 c^2

that this

K.E. = \frac{1}{2}m_0 v^2 + ...

wiki can

P = \frac{m_0 v}{\sqrt{1 - \frac{v^2}{c^2}} }

now

m = \frac{m_0}{\sqrt{1-\frac{v^2}{c^2}} }

do

K.E. = m c^2 - m_0 c^2.

formulae

E = m c^2

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Test (last edited 2010-03-31 10:00:51 by DavidCollien)